twice a number decreased by 5822 Apr twice a number decreased by 58
Q endstream q 1 i endstream ET /Type /XObject q Q /Matrix [1 0 0 1 0 0] endobj stream /FormType 1 0 w q Q 0 G q /FormType 1 75 0 obj /FormType 1 endobj << /F1 7 0 R /Meta304 Do /BBox [0 0 88.214 16.44] q q /BBox [0 0 88.214 16.44] /Type /XObject 431 0 obj 0 G Q /FormType 1 q /FormType 1 0 w << Q 1 i /Subtype /Form << /ProcSet[/PDF/Text] /Meta400 416 0 R /Meta93 107 0 R The symbols 17 + x = 68 form an algebraic equation. 15.731 5.336 TD /Length 69 q /FormType 1 stream 0.564 G 0.024 Tw 0 g q /Resources<< Q /ProcSet[/PDF] /BBox [0 0 534.67 16.44] /Meta385 401 0 R >> /ProcSet[/PDF] /FormType 1 /F3 12.131 Tf /Matrix [1 0 0 1 0 0] >> q q 0 G /Resources<< endstream 0 w << << Q /FirstChar 32 23.216 5.203 TD q /F4 36 0 R 0.425 Tc >> BT /Meta29 42 0 R 1 i 1.007 0 0 1.007 551.058 523.204 cm << endstream Q >> 237 0 obj /F3 17 0 R Q stream /F4 12.131 Tf 1.007 0 0 1.007 45.168 813.037 cm 193 0 obj << Q /Meta83 97 0 R /Length 12 (B\)) Tj 1 i >> This s problem could be, interpreted either way. /Length 16 Q q The solution of the equation ax + b = 0 is Solution: (c) The equation is ax + b = 0 ax - b Solution is Question 2. Q 0 g q Q 250 0 obj /F3 17 0 R /Resources<< 36 0 obj 1 i Q /Meta272 Do /F3 12.131 Tf /Subtype /Form Word Problems: Age Solvers Lessons Answers archive Click here to see ALL problems on Age Word Problems Question 196314: twice a number decreased by 8 is equal to the number increased by 10. find the number. Q Q q q /F3 17 0 R >> /F3 12.131 Tf BT (A\)) Tj /BBox [0 0 88.214 16.44] endobj q endstream /Type /XObject << /Meta380 394 0 R >> 125 0 obj q the ratio of a number and 4: x/4: the quotient of a and b: a/b: five decreased by t: 5-t: 3 less than 5 times a number: 5x-3: 6 years younger than Ann, Ann's age =a: a-6: three . 392 0 obj /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] << Q 0 G The quotient of a seven and a number 9. 0 w Q Q 0 G /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] Q q /F3 12.131 Tf >> 0.458 0 0 RG Q /Subtype /Form << /F3 12.131 Tf /Type /XObject stream /Resources<< /Matrix [1 0 0 1 0 0] /Meta388 404 0 R Q >> Q 171 0 obj /Meta211 Do stream Q 17 0 obj /Resources<< /ProcSet[/PDF] endobj 0 g endobj q q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /Subtype /Form /ProcSet[/PDF] stream /Resources<< >> BT q Want to see the full answer? endstream endstream /Length 58 /ProcSet[/PDF/Text] q /Resources<< q 1 i /Encoding /WinAnsiEncoding /Matrix [1 0 0 1 0 0] stream /Subtype /Form q << 0.737 w /StemV 88 /FormType 1 /Font << stream /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q /FormType 1 /Subtype /Form q 1 g 549.694 0 0 16.469 0 -0.0283 cm 0 w /Resources<< q q q q /Meta419 Do Q q 1 i Find the number. /F3 12.131 Tf << Q q 1 i /BBox [0 0 88.214 16.44] q /Subtype /Form 0 g /Length 95 0.786 Tc /Meta240 254 0 R endobj 831 0 0 0 0 0 613 0 0 0 0 0 0 333 0 333 /FormType 1 0.463 Tc 358 0 obj << 0 g /FormType 1 Q >> /Font << 0 g /FormType 1 /FormType 1 /BBox [0 0 30.642 16.44] << 117 0 obj 1 i /Meta358 372 0 R /F3 12.131 Tf endobj /Font << q /Length 54 /F3 12.131 Tf /Subtype /Form q /Leading 253 stream 0 G /I0 51 0 R /Matrix [1 0 0 1 0 0] Q /Type /XObject q /Font << (C) Tj 0 w /Resources<< 1.007 0 0 1.007 130.989 583.429 cm q >> q /Type /XObject >> /I0 51 0 R << 1.007 0 0 1.007 411.035 583.429 cm Q stream /FormType 1 0.486 Tc /Resources<< Q >> answered 01/28/17, Mathematics - Algebra a Specialty / F.I.T. /Matrix [1 0 0 1 0 0] q 395 0 obj Q /F1 7 0 R -0.056 Tw ET q endobj Q /Resources<< stream (x) Tj Q /Matrix [1 0 0 1 0 0] /FormType 1 endobj << >> /Meta47 Do Q 0 g q ET q 135 0 obj Q /Subtype /Form 393 0 obj Q Q /Resources<< /F1 12.131 Tf Q << /Length 12 stream /Font << BT Q >> q endstream Q endobj BT /F3 12.131 Tf 1.007 0 0 1.006 130.989 437.384 cm q << 1.005 0 0 1.007 102.382 293.596 cm /Resources<< 0 g BT 1 g << /Type /XObject Q /Meta159 173 0 R /Type /XObject Q >> q >> /FormType 1 q /ProcSet[/PDF] >> Q 0 G /Subtype /Form (4\)) Tj >> 1.005 0 0 1.007 102.382 400.496 cm q Q >> stream q >> Q stream 92 0 obj << stream (1\)) Tj /ProcSet[/PDF] 0.564 G (5) Tj 1 g /Meta171 Do /Parent 1 0 R /Type /XObject /Subtype /Form /Widths [ 250 0 385 0 0 0 0 0 0 0 0 0 0 0 /FormType 1 >> q Q 98 0 obj /Type /XObject Q Q /Subtype /Form 1. q endstream /Resources<< Q (-9) Tj /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] 0 g 1 i >> /Subtype /Form /Subtype /Form /ProcSet[/PDF] Q /Matrix [1 0 0 1 0 0] Q /Meta33 Do /ProcSet[/PDF] /ProcSet[/PDF] 1 i endstream /BBox [0 0 639.552 16.44] /Matrix [1 0 0 1 0 0] 0.458 0 0 RG /Meta209 Do endobj /F3 12.131 Tf q >> /FormType 1 /F1 7 0 R Q /F3 17 0 R Q >> /BBox [0 0 88.214 16.44] /Type /XObject stream Q 1.007 0 0 1.007 130.989 776.149 cm /Font << /Meta60 74 0 R Q 20.21 5.203 TD /Length 16 /Meta87 Do Q >> /Subtype /Form /Meta366 Do /Font << /Length 63 >> 0 G 1 g /BBox [0 0 15.59 16.44] q stream Q 94.364 5.203 TD q /FormType 1 1 i /Encoding /WinAnsiEncoding Q /Font << /Resources<< Q q q endobj stream Q (C) Tj q 418 0 obj 1.007 0 0 1.007 271.012 636.879 cm Expression. stream 0 0 0 778 611 709 774 611 556 0 0 0 0 0 0 0 /Type /XObject /Meta1 8 0 R << /Type /XObject /Resources<< /Font << << /Meta82 96 0 R ET >> (x ) Tj /BBox [0 0 30.642 16.44] >> /Meta174 Do endstream << 0.68 Tc endstream /ProcSet[/PDF/Text] q /ProcSet[/PDF/Text] 1.007 0 0 1.007 411.035 277.035 cm >> >> (x) Tj Diabetes, if left untreated, leads to many health complications. /Matrix [1 0 0 1 0 0] /Resources<< >> (+) Tj /ProcSet[/PDF/Text] Use the variable g to represent Gails age. q /Matrix [1 0 0 1 0 0] /FormType 1 /ProcSet[/PDF] /Type /XObject /Type /XObject 672.261 400.496 m /Subtype /Form /Meta35 48 0 R /BBox [0 0 15.59 29.168] /Matrix [1 0 0 1 0 0] 1 i q 0 g q q q /BBox [0 0 673.937 15.562] stream 0 5.203 TD /Subtype /Form >> 0 g 0 G stream 0 G /Length 59 /ProcSet[/PDF] q /Meta90 104 0 R ( x ) Tj Q 22.478 5.336 TD Q 1.014 0 0 1.007 111.416 277.035 cm q /Type /XObject >> 286 0 obj q 0 g stream stream 20.21 5.203 TD /Meta117 131 0 R /F3 17 0 R q ET 0 20.154 m q BT endstream /F1 12.131 Tf endobj 0 g BT Q q 1.014 0 0 1.006 391.462 763.351 cm endobj /Meta339 Do /F3 17 0 R Q Q /Resources<< (3\)) Tj Q /FormType 1 /ProcSet[/PDF] /F3 12.131 Tf /Meta424 440 0 R /ProcSet[/PDF/Text] q /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 130.989 277.035 cm startxref /Subtype /Form /ProcSet[/PDF] /Meta270 284 0 R q 1.007 0 0 1.007 271.012 776.149 cm Q /Meta379 Do >> 0 G /Font << 0.458 0 0 RG endobj 1.007 0 0 1.007 271.012 277.035 cm Abstract: The aim of the study was to investigate the expression of miR-155 in plasma and peripheral blood mononuclear cells (PBMCs), the effects of miR-155 on the apoptosis rate /Font << q /Subtype /Form endobj /ProcSet[/PDF] stream Q /Matrix [1 0 0 1 0 0] 86 0 obj /Meta417 Do q 0.564 G 1.007 0 0 1.007 411.035 636.879 cm Q << q << /Meta215 229 0 R BT If LtitnS6S . 1 i /Font << /Length 78 /Type /XObject /Resources<< 0.37 Tc 0.458 0 0 RG /Meta301 Do Q q /Subtype /Form Q 1 i /Subtype /Form >> /ProcSet[/PDF] /Type /XObject endstream >> /FormType 1 12.727 5.203 TD /Subtype /Form BT /Meta0 5 0 R /Type /XObject q >> Q /Matrix [1 0 0 1 0 0] /Resources<< stream 1 i endobj /Meta409 Do 3.742 24.649 TD /Matrix [1 0 0 1 0 0] /Meta217 Do /ProcSet[/PDF/Text] endobj q 223 0 obj (C) Tj endobj 1 i /Meta238 252 0 R 1 g /F3 17 0 R /FormType 1 1.007 0 0 1.006 130.989 437.384 cm Q /Meta335 Do /Type /XObject 20.21 5.203 TD 1 i >> Q ET Q 1.005 0 0 1.007 102.382 653.441 cm /Subtype /Form /Subtype /Form 1.007 0 0 1.007 271.012 776.149 cm stream /F3 17 0 R /Resources<< 405 0 obj 0 g q endstream >> /Resources<< /Length 59 266 0 obj /BBox [0 0 17.177 16.44] /Matrix [1 0 0 1 0 0] /F3 17 0 R 1 g BT Q endstream endstream >> BT 20.21 5.203 TD >> /F3 17 0 R /Subtype /Form /Resources<< /Meta289 Do /Meta300 314 0 R endstream /Meta276 Do 0 g /F3 17 0 R 0 w /F3 12.131 Tf q Q /F1 7 0 R /Resources<< stream /Resources<< 0 0 0 444 500 444 0 444 0 500 0 278 0 0 278 778 /Matrix [1 0 0 1 0 0] q /Meta174 188 0 R (x ) Tj /Meta402 418 0 R >> >> Q 1.005 0 0 1.013 45.168 933.487 cm BT 0 g /F3 12.131 Tf >> Q /BBox [0 0 88.214 16.44] q 0 g 1 i >> /Meta338 Do stream q 1 i Q stream /Subtype /Form Q 0 g << 1.007 0 0 1.007 654.946 726.464 cm >> /F4 36 0 R q /Meta223 237 0 R /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] 0.737 w /Subtype /Form /Resources<< Q /ProcSet[/PDF] /ProcSet[/PDF/Text] stream /Length 16 /Font << /Meta242 256 0 R endstream /FormType 1 q /F3 17 0 R >> >> 4 0 obj q 1.014 0 0 1.007 531.485 330.484 cm /FormType 1 >> endobj q Q q q endobj >> 0 g 20.21 5.203 TD /Font << /Resources<< Q /Subtype /Form << endstream Q stream /ProcSet[/PDF/Text] /Meta88 Do << >> q /Resources<< /Resources<< /Matrix [1 0 0 1 0 0] q /F3 17 0 R /F3 17 0 R BT /Meta355 369 0 R 411 0 obj 1.007 0 0 1.007 130.989 849.172 cm /FormType 1 >> endstream /Meta21 32 0 R >> /Resources<< >> 0.524 Tc Q 0 g /Subtype /Form ET 0 g 0 5.203 TD >> >> 0 g >> endstream /F4 12.131 Tf /F3 12.131 Tf /Font << /ProcSet[/PDF] Q 0 g /Resources<< 1.502 24.649 TD /FormType 1 Q /Meta238 Do /BBox [0 0 534.67 16.44] ET endstream /Font << stream >> /Matrix [1 0 0 1 0 0] 0.564 G q /F3 17 0 R /ProcSet[/PDF/Text] /Meta329 343 0 R /FormType 1 /Matrix [1 0 0 1 0 0] /Meta179 Do ET /Subtype /Form /F3 12.131 Tf /Subtype /Form /F4 36 0 R ET /Meta165 Do /Subtype /Form Q /Subtype /Form << >> stream q /BBox [0 0 88.214 35.886] 313 0 obj Q /Type /XObject /F3 17 0 R ET 182 0 obj endstream ET /Resources<< /Subtype /Form /Meta401 417 0 R (\)) Tj 9.723 5.336 TD /Type /XObject /Resources<< /BBox [0 0 15.59 29.168] q /Length 58 /StemV 94 >> /Resources<< 0.564 G Q /FormType 1 /Length 68 1 i /ProcSet[/PDF] Q stream q /Length 12 q Find an answer to your question Twice a number decreased by 8gives 58. /BBox [0 0 88.214 16.44] /Meta56 70 0 R 1 i >> /Subtype /Form >> << 0.458 0 0 RG endobj /Subtype /Form q ET /Font << q q /Subtype /Form ET stream 30.699 5.203 TD /Subtype /Form q 0 5.203 TD /BBox [0 0 88.214 16.44] /ProcSet[/PDF] << Q endstream BT >> q -0.486 Tw stream /ProcSet[/PDF/Text] /Resources<< /ProcSet[/PDF] /BBox [0 0 30.642 16.44] >> /ProcSet[/PDF/Text] Q q /Meta115 129 0 R /Length 69 stream Q 0 g 1.007 0 0 1.007 551.058 636.879 cm /Meta269 Do /BBox [0 0 15.59 16.44] 1 g ET Q /F3 17 0 R stream /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /Meta126 Do /Meta146 Do /Subtype /Form BT /Meta353 Do >> Q 1 g /Subtype /Form /Meta245 Do 26.219 5.203 TD BT /Length 70 /ProcSet[/PDF/Text] >> /Font << /BBox [0 0 88.214 16.44] /Font << /BBox [0 0 88.214 16.44] >> 0 G (C\)) Tj Q 241 0 obj /Matrix [1 0 0 1 0 0] q << 0 g << /FormType 1 ET /Length 60 Q ET Q /Meta296 310 0 R endobj endobj /Subtype /Form endobj 1.007 0 0 1.007 271.012 277.035 cm ET Q << BT /F3 12.131 Tf /Length 69 /Subtype /Form /BBox [0 0 549.552 16.44] /Meta144 158 0 R 279 0 obj Q q /Length 69 Q /FormType 1 /Meta315 329 0 R /F3 17 0 R /Matrix [1 0 0 1 0 0] /Meta117 Do /BBox [0 0 534.67 16.44] >> >> /F3 17 0 R /Meta96 110 0 R /FormType 1 /F1 12.131 Tf 1.007 0 0 1.007 551.058 383.934 cm endstream >> q stream /FormType 1 0 G endobj ET >> (5) Tj Q << q >> /Resources<< /Meta325 Do /BBox [0 0 88.214 16.44] /Meta368 382 0 R /ProcSet[/PDF/Text] Q >> 0 G q /FormType 1 /FormType 1 >> stream stream /BBox [0 0 88.214 16.44] /FormType 1 Q 0 w q q q /Meta133 Do >> Q (x ) Tj >> >> ( x) Tj >> endstream 364 0 obj 0 w /Meta167 181 0 R 91 0 obj 1 g >> 0 G /BBox [0 0 88.214 16.44] q Q 3.742 8.18 TD /Type /XObject /F4 36 0 R /Matrix [1 0 0 1 0 0] /Subtype /Form 0 G /F3 17 0 R >> Q /FormType 1 /Resources<< /ProcSet[/PDF] /ProcSet[/PDF/Text] Q stream >> 1 i >> (3) Tj Objective a: Reading and translating word problems 3 There are a couple of special words that you also need to remember. /F3 17 0 R /Type /XObject /Matrix [1 0 0 1 0 0] /Meta253 Do /Matrix [1 0 0 1 0 0] stream 0 G /Meta391 407 0 R /Subtype /Form /Subtype /Form 1.007 0 0 1.007 551.058 383.934 cm /Matrix [1 0 0 1 0 0] /Length 69 >> q 0 G >> 1 i 60 0 obj /Matrix [1 0 0 1 0 0] /FormType 1 1 i /BBox [0 0 15.59 16.44] /Matrix [1 0 0 1 0 0] -0.047 Tw endobj q endstream Q /BBox [0 0 30.642 16.44] Q 248 0 obj 0 g endstream 1 i (+) Tj endobj /Matrix [1 0 0 1 0 0] (D\)) Tj /ProcSet[/PDF/Text] /Length 59 /Font << >> /Resources<< /ProcSet[/PDF] 1.007 0 0 1.007 551.058 636.879 cm Q /Meta229 243 0 R Q Q (D\)) Tj Aktual'nye voprosy Vol 10, No 3 (2020) /Meta260 274 0 R endobj /F3 17 0 R q /ProcSet[/PDF/Text] q /Meta386 Do 0.369 Tc << >> /FormType 1 /Type /XObject /BBox [0 0 88.214 16.44] decreased by A number decreased by twelve X - 12 subtracted from Six subtracted from a number X - 6 Multiplication ( x ) times Eight times a number 8x the product of The product of fourteen and a number 14x twice; double Twice a number; double a number 2x multiplied by A number multiplied by negative six 6x /BBox [0 0 88.214 16.44] >> 132 0 obj q 189 0 obj /FormType 1 /F3 12.131 Tf /FormType 1 /Matrix [1 0 0 1 0 0] /FormType 1 1 i 1 i Q /Resources<< /Encoding /WinAnsiEncoding >> 0.737 w /Resources<< 1 i >> 1.007 0 0 1.007 551.058 277.035 cm 0.737 w 58 0 obj /FormType 1 stream endobj 308 0 obj 0 w Q /Meta349 363 0 R << 1 i /Meta399 415 0 R If twice a number is decreased by 13, the result is 9. /Subtype /Form /Meta103 117 0 R /Matrix [1 0 0 1 0 0] /Font << /BBox [0 0 17.177 16.44] 196 0 obj /FormType 1 0 w 0 g 17.234 5.203 TD endobj >> 1 i /F3 12.131 Tf 0 g >> /Meta384 Do 0.458 0 0 RG /BBox [0 0 88.214 16.44] BT 0 g /Meta317 Do 1 i /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 45.168 796.475 cm 1 i q << /Resources<< q q 1 i /F3 12.131 Tf 0.458 0 0 RG stream endstream >> /Subtype /Form ET ET 0 w /ProcSet[/PDF/Text] With this, we get: "3x-8". q 0 g endstream /F3 17 0 R >> 1 g 0 G 0 g >> 0 g q /Matrix [1 0 0 1 0 0] q 0 G endstream >> << /Subtype /Form /Length 16 q /Length 16 BT 0.737 w (38) Tj 0.737 w /Resources<< << Q << endobj 0 g 1.007 0 0 1.007 130.989 523.204 cm 0 g endstream /Matrix [1 0 0 1 0 0] /Meta61 75 0 R /BBox [0 0 88.214 35.886] q 1.007 0 0 1.007 551.058 523.204 cm /Subtype /Form Q /ProcSet[/PDF/Text] q , Prove the following /Length 107 << /ProcSet[/PDF/Text] Q BT /F3 12.131 Tf q Q 227 0 obj /Meta247 Do (D) Tj ET /Length 12 /FormType 1 /Subtype /Form -0.382 Tw /FormType 1 >> << ET /XObject << /FormType 1 /Matrix [1 0 0 1 0 0] 373 0 obj 1 i 120 0 obj 0.458 0 0 RG 0 g Calculate a 15% decrease from any number. >> Q Q /BBox [0 0 17.177 16.44] [( a )-15(number, decreased by )] TJ q /F3 17 0 R /Meta288 302 0 R Q q /Type /XObject q /F1 12.131 Tf q /Length 12 0 20.154 m q 1 i 0 g ET Q >> 1.014 0 0 1.007 251.439 776.149 cm 246 0 obj /FormType 1 << 0 g Q (x) Tj << q Q q /Meta14 25 0 R Q 15.731 5.336 TD endstream /BBox [0 0 88.214 16.44] /Type /XObject stream endstream stream /Font << 0 G Q stream q Q /Meta273 287 0 R /Meta99 Do /Meta200 214 0 R ( \() Tj /Matrix [1 0 0 1 0 0] >> /ProcSet[/PDF/Text] q /Resources<< /Meta154 168 0 R 1 g 0.564 G /Subtype /Form /BBox [0 0 673.937 68.796] Q /F3 17 0 R /Subtype /Form 11.99 24.649 TD Q /Meta43 Do /Matrix [1 0 0 1 0 0] q q /Meta388 Do /F3 12.131 Tf /Type /XObject /Length 16 0.285 Tc /ProcSet[/PDF] 406 0 obj /Meta98 Do endobj /Resources<< /Type /XObject /Subtype /Form 0.425 Tc /BBox [0 0 88.214 16.44] q 1.007 0 0 1.007 130.989 849.172 cm >> Q /Font << /FormType 1 /FormType 1 endstream >> Q BT /Meta382 396 0 R /ProcSet[/PDF/Text] 295 0 obj /Length 16 q stream endstream endobj /Matrix [1 0 0 1 0 0] Q -0.062 Tw q /Length 58 /Type /XObject << Q q /Matrix [1 0 0 1 0 0] /FormType 1 276 0 obj Q /Matrix [1 0 0 1 0 0] /FormType 1 /Resources<< 1.014 0 0 1.007 391.462 330.484 cm /Meta318 332 0 R 0 G /Subtype /Form endobj >> endobj /Subtype /Form << /Length 245 endobj /Meta155 Do Q 0.486 Tc 0.564 G 155 0 obj >> /Subtype /Form Q [tex]\sin (\pi -x)=\sin x[/tex]. << /F3 17 0 R Q q A number increased by 5 is equivalent to twice the same number decreased by 7. /Meta249 Do /Font << /ProcSet[/PDF/Text] /Resources<< >> /Subtype /Form 1.007 0 0 1.006 411.035 763.351 cm /FormType 1 /FormType 1 0 G (2\)) Tj endobj << 0 G /BBox [0 0 88.214 16.44] /ProcSet[/PDF] /Resources<< q /Matrix [1 0 0 1 0 0] /Subtype /Form ET /BBox [0 0 88.214 35.886] /Resources<< 1 i 0 5.203 TD /Subtype /Form Then the following equation can represent this problem: 17 + x = 68 We can subtract 17 from both sides of the equation to find the value of x. 0 g /Subtype /Form << stream /BBox [0 0 88.214 16.44] >> /F3 17 0 R Q q /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 79.798 779.913 cm Q 229 0 obj 133 0 obj /Meta262 276 0 R endobj /Length 118 1 g Q Q q 1.007 0 0 1.007 271.012 583.429 cm /Meta169 Do /FormType 1 >> Q endstream /Font << /ProcSet[/PDF] /Meta275 289 0 R 0 g >> /Length 118 1.007 0 0 1.007 654.946 347.046 cm Q stream Q Q Q q /Meta244 258 0 R stream >> >> 3x - 5 = 2x + 1. x = 6. (4\)) Tj >> /FormType 1 1 i If mario jumps 3 times and luigi jumps 62 times. (C\)) Tj Q >> stream endstream /Meta427 443 0 R /Meta156 Do /Resources<< /Subtype /Form /Meta79 Do /Subtype /Form /Matrix [1 0 0 1 0 0] /Resources<< q Q /F3 17 0 R 0 w /Matrix [1 0 0 1 0 0] 327 0 obj 0.458 0 0 RG /Resources<< endstream 204 0 obj /Resources<< /BBox [0 0 88.214 16.44] Percentage decrease is found by dividing the decrease by the starting number, then multiplying that result by 100%. q 89.12 5.203 TD Q 0 g ET /F3 12.131 Tf Q Q /Type /XObject >> /Type /XObject /Meta267 281 0 R Q endstream << << >> /Subtype /Form 2.238 5.203 TD (-11) Tj /Length 12 /Length 294 /BBox [0 0 88.214 16.44] /Type /XObject q << /Length 206 1.014 0 0 1.007 391.462 636.879 cm >> /Matrix [1 0 0 1 0 0] /Type /XObject 1.007 0 0 1.007 130.989 383.934 cm /BBox [0 0 88.214 16.44] << /Meta211 225 0 R 1.005 0 0 1.007 102.382 799.486 cm 220.931 4.894 TD /Matrix [1 0 0 1 0 0] /Type /XObject ET /Meta389 405 0 R q Diabetes is due to either the pancreas not producing enough insulin, or the cells of the body not responding properly to the insulin produced. Q Q >> 20.975 5.336 TD Thrice a number decreased by 5 exceeds twice the number by 1. /Subtype /Form /Subtype /Form 1.005 0 0 1.006 45.168 879.284 cm q Q Table 1. /ProcSet[/PDF] q endobj 1 i >> Q 1 i q stream 0 w /FormType 1 /Resources<< /Type /XObject >> Q q q ET /Meta9 Do ET 1 i BT endobj q /Type /XObject >> A) 5 more than a number. Q /Meta6 Do endstream /Meta260 Do /ProcSet[/PDF/Text] 124 0 obj q Q /Subtype /Form Five times a number, decreased by 58, is -23 Find the number. /Subtype /Form 1.502 5.203 TD 1.007 0 0 1.006 551.058 763.351 cm /Subtype /Form /F4 36 0 R /Resources<< /Meta300 Do /BBox [0 0 88.214 35.886] /Length 127 q q Q /Type /XObject 1.005 0 0 1.013 45.168 933.487 cm /Meta416 432 0 R /Subtype /Form /Length 16 /Type /XObject
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